If the circumference of a circle increases with 2pie to 3pie.find the ratios of the area.
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circumference of earlier circle= 2πr= 2π
so r= 1
area of earlier circle= πr2= π
circumference of another circle=2πR= 3π
R= 3/2
area of that circle= π (R2)= π (3/2)2= 9/4π
ratio= (π)/(9/4π)=4/9
the ratio of their areas are 4:9....
so r= 1
area of earlier circle= πr2= π
circumference of another circle=2πR= 3π
R= 3/2
area of that circle= π (R2)= π (3/2)2= 9/4π
ratio= (π)/(9/4π)=4/9
the ratio of their areas are 4:9....
yasvanth:
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Answered by
1
Circumference of a 1 circle =2pie r h
circumference of a 2 circle=3 pie r h
Ratio=2pie r h/3pie r h
Ratio =2/3
circumference of a 2 circle=3 pie r h
Ratio=2pie r h/3pie r h
Ratio =2/3
thnks sister
u r marvelous!
Wlcm
sorry but its the wrong answer....
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