if the circumference of a circle with 3.5cm and O is 22cm. find the perimeter of the quarter of the circle
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as r = 3.5cm
perimeter of quadrant = 90*2πr/360 + r + r
perimeter of quadrant = πr/2 + 2r
perimeter of quadrant = r (π/2 +2)
perimeter of quadrant = 3.5(22/7*2 +2)
perimeter of quadrant = 3.5 (22/14 +2)
perimeter of quadrant = 3.5 ( (22+28)/14)
perimeter of quadrant = 3.5 (50/14)
perimeter of quadrant = 3.5 * 25/7
perimeter of quadrant = 25/2
perimeter of quadrant = 12.5 cm
thus perimeter of quadrant is 12.5cm
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perimeter of quadrant = 90*2πr/360 + r + r
perimeter of quadrant = πr/2 + 2r
perimeter of quadrant = r (π/2 +2)
perimeter of quadrant = 3.5(22/7*2 +2)
perimeter of quadrant = 3.5 (22/14 +2)
perimeter of quadrant = 3.5 ( (22+28)/14)
perimeter of quadrant = 3.5 (50/14)
perimeter of quadrant = 3.5 * 25/7
perimeter of quadrant = 25/2
perimeter of quadrant = 12.5 cm
thus perimeter of quadrant is 12.5cm
Hope it helps you
please mark it as BRAINLIST if it helps you
omshishodiya:
I didn't understand
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i write answer i think u dont understand from where 2r comes
no I don't understand from first please explain in detail
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