Question

If the class mark and class size of a class are 6 and 12 respectively, then the upper limit of the class is

Answer 1

Answer:

12

Step-by-step explanation:

Class mark = 6

Class size = 12

let x be the lower limit of the class,

then the upper limit of the class will be x + 12 , as the class size is 12

class mark = (upper limit + lower limit)/2

              6  = (x + x + 12)/2

              6  = (2x + 12)/2

             12  = 2x + 12

              0  = 2x

              x   = 0

Therefore, the upper class limit is 12

Answer 2

The upper limit of the class is 12

Given :

The class mark and class size of a class are 6 and 12 respectively

To find :

The upper limit of the class

Solution :

Step 1 of 2 :

Write down class mark and Class size

Here it is given that class mark and class size of a class are 6 and 12 respectively

Step 2 of 2 :

Find upper limit of the class

Hence the required upper limit of the class

$\displaystyle \sf{ = Class \: mark + \frac{Class \: size}{2} }$

$\displaystyle \sf{ = 6+ \frac{12}{2} }$

$\displaystyle \sf{ = 6+ 6 }$

$\displaystyle \sf{ = 12 }$

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