Question

If the class mark of continuous frequency distribution are 22,30,38 ,46,54,62 then find the class corresponding to the class mark 46

Answer 1

Since the class marks are equally spaced

Difference between class marks=h=8

If a is class mark, h is the class difference,then

lower limit and upper limit of class are:a-h/2 and a+h/2

lower limit  :46-8/2  =46-4=42

upper limit: 46+8/2 =46+4=50

Hence the class corresponding to marks 46 is 42-50

Answer 2

The corresponding class mark for 42 is 50

Given:

Frequency distribution of marks are "22", "30", "38", "46", "54", "62"

To find:

The corresponding class mark

Answer:

Given that

Class marks are "22", "30", "38", "46", "54", "62"

The difference of class marks are, h=8

Where,

a = class marks and

h =class difference.

$Lower \ limit \ of \ class, = a - \frac {h} {2}$

$Upper \ limit \ of \ class, = a + \frac {h} {2}$

$Lower \ limit = 46 - \frac {8}{2}$

$= 46 - 4 = 42$

$Upper \ limit = 46 + \frac {8}{2}$

$= 46 + 4$

$= 50$