If the coefficient of x^2r in the expansion of (x+1/x^2)n-3 is not zero ,then (n-2r/3) is
1) a rational number 2) a positive integer
3) a negative integer
4) a positive rational number
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Answered by
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Answer:
A positive integer second is a correct option
Answered by
1
Step-by-step explanation:
Given = x^2r is the expansion of( x+1/x2)^n-3
we know that r= np-k/p+q
a=1,b=1,p=1,q=2,n=n-3,k=2r
r=(n-3)×1-2r/1+2
r=n-3-2r/3
Here, n-3-2r/3 is in improper fraction . so, change this into mixed fraction
r= n-2r/3-1 is not equal to zero
so, n-2r/3=1
Here r is not equal to zero
By this we can conclude that r=n-2r/3 =1
is a positive integer
hope it is helpful to you
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