Question

. If the common difference of an A.P. is 3, then find a20 – a15

Answer 1

NANBA..

Step-by-step explanation:

Let the first term of the AP be a.

an = a(n − 1)d

a20 – a15 = [a + (20 – 1)d] – [a + (15 – 1)d]

= 19d – 14d

= 5d

=5*3

=15

Answer 2

Answer:

hey frnd here is your answer

Step-by-step explanation:

Given - common difference of A.P=3

To Find- a20-a15

Solution-

a20=a+19d and a15=a+14d

so a20-a15= (a+19d)-(a+14d)

=a+19d-a-14d

= 19d-14d

=5d

a20-a15=5(3)=15.

So frnd your final answer is 15.

i hope you get your answer

thnx for asking

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