Question

If the common difference of an AP is -6, then find a16-a12​

Answer 1

Answer:

Given:-

• Common Difference = -6

To Find:-

• $a_{16} \: - \: a_{12}$

Formula used:-

• $a_{n} = a + (n-1)d$

Solution:-

From question,

⟾ $a_{16} \: - \: a_{12}$

⟾ $a + (16-1)×(-6) - [a + (12-1)×(-6)]$

⟾ $a + 15×(-6) - (a + 11×(-6)$

⟾ $a + (-90) - (a + (-66)$

⟾ $a - 90 - a + 66$

⟾ $- 90 + 66$

⟾ $-24$

Hence, Value of ${\bold{a_{16} \: - \: a_{12}}}$ is -24.

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Answer 2

Step-by-step explanation:

CD = -6

Formula used:-

a{n} = a + (n-1)d

an =a+(n−1)d

From question,

a{16} - a{12}

= a + (16-1)×(-6) - [a + (12-1)×(-6)]

= a + 15×(-6) - [a + 11×(-6)]

= a + (-90) - [(a + (-66)]

⟾ a - 90 - a + 66

⟾ - 90 + 66

⟾ -24

value of a16- a12 = -24