Question

If the compound interest for 3 year is rs. 1500 at the annual interest rate of 5%
for the 1st year and 5 1/2% for the 2nd year and 6% for the 3rd year, calculate the
principal?

Please do with procedure very important to me ​

Answer 1

P = ₹8610.05

Step-by-step explanation:

$amount \: = P(1 +\frac{R_{1}}{100})(1+\frac{R_{2}}{100})(1 +\frac{R_{3}}{100}) \\ CI + P =P(1 +\frac{R_{1}}{100})(1+\frac{R_{2}}{100})(1 +\frac{R_{3}}{100}) \\1500 +P = P(1 +\frac{5}{100})(1+\frac{5.5}{100})(1 +\frac{6}{100}) \\ 1500 +P = P(1 +\frac{1}{20})(1+\frac{11}{200})(1 +\frac{3}{50}) \\ 1500 +P = P(\frac{21}{20})(\frac{211}{200})(\frac{53}{50}) \\ 1500 + P = \frac{234843}{200000} P \\\frac{234843}{200000} P - P = 1500 \\ \frac{34843}{200000} P= 1500 \\ P = 1500 \times \frac{200000}{34843} \\P = 8610.05$

Answer 2

$\large\mathcal \red \bigstar{\underline{\purple{GIVEN:-}}}$

CI=₹1500

rate for 1st year=5%

rate for 2nd year=5.5%

rate for 3rd year=6%

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$\large\mathcal \red \bigstar{\underline{\orange{Find:-}}}$

Principal of the the following C.I

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$\large\mathcal \red \bigstar{\underline{\pink{Formula:-}}}$

Amount=Principal + C.I

Amount=P(1+ r/n)^nt

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$\large\mathcal \red \bigstar{\underline{\green{Solution:-}}}$

(IN THE ATTACHMENT)