Math, asked by biswajit4074, 1 month ago

If the compound interest in the third year at 8% p.a. on a certain sum is 3600, then what is the difference between the compound interest in the 4th and 5th year? (nearest to an integer in *)​

Answers

Answered by sakshamawasthi1000
2

Step-by-step explanation:

Compound interest for the 4th year = 3600 + (3600×8×1)/100.

= 3600+288.

=Rs. 3888.

Compound interest for the 5th year = 3888 +(3888×8×1)/100.

= 3888 + 311.04.

= Rs. 4199.04.

Difference between the compound interest in the 4th and 5th year = 4199.04

- 3888. = Rs.311.04. Answer.

Answered by amitnrw
0

Given : the compound interest in the third year at 8% p.a. on certain sum is ₹3600,

To Find :  the difference between the compound interest in the 4th and 5th year

Solution:

Initial Amount P

Compound interest in 3rd year = 3600

Compound interest in 4th year =  Compound interest in 3rd year  + inetrest on Rs 3600

= 3600 +  3600 * 8 *  1/100

= 3600 + 288

= 3888  Rs

 the difference between the compound interest in the 4th and 5th year

=  interest on interest earned in 4th year

= 3888 x 8 * 1/100

= 311.04  Rs

the difference between the compound interest in the 4th and 5th year  = 311.04  Rs

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