if the compound interest on 12000 for 3 years is 3972 find the rate of interest per annum
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Answered by
48
Hey sup!
P=12000.
CI=3972.
Amount=12000+3972=15972.
Let rate of interest be r%.
T=3years.
As per the question,
A=P(1+r/100)^T.
15972=12000(1+r/100)^3.
15972/12000=(1+r/100)^3.
Dividing 15972/12000 by 12.
1331/1000=(1+r/100)^3.
(11/10)^3=(1+r/100)^3.
11/10=1+r/100.
11/10=(100+r)/100.
11/10×100=100+r.
110=100+r.
r=110-100.
r=10%.
The interest per annum is 10%.
Hope it helps.
P=12000.
CI=3972.
Amount=12000+3972=15972.
Let rate of interest be r%.
T=3years.
As per the question,
A=P(1+r/100)^T.
15972=12000(1+r/100)^3.
15972/12000=(1+r/100)^3.
Dividing 15972/12000 by 12.
1331/1000=(1+r/100)^3.
(11/10)^3=(1+r/100)^3.
11/10=1+r/100.
11/10=(100+r)/100.
11/10×100=100+r.
110=100+r.
r=110-100.
r=10%.
The interest per annum is 10%.
Hope it helps.
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1
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