Question

If the compounds of air are N2,78%; O2,21%; Ar,0.9% and CO2,0.1% by volume, what would be the molecular weight of air??

Answer 1

Heya......✋
Answer is in attachment.....
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Answer 2

Answer:

The volume ratio of the gases will be the same as their mole ratios ( Avogadro's principal)

$so \: mol. \: wt \: of \: air \: = \\ \frac{78 \times 28 + 21 \times 32 + 0.9 \times 40 + 0.1 \times 44}{78 + 21 + 0.9 + 0.1} \\( wt. \: in \: g \: per \: mole) \: \\ \: \: \: \: \: \: \: \: \: \: = 28.964$