Question

If the concentration of given solution of KOH is 0.01M. Calculate the pOH and pH of the solution

​

Answer 1

pOH and pH of the solution is 2 and 12 respectively.

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

Acids have pH ranging from 1 to 6.9 and bases have pH ranging from 7.1 to 14.Neutral substances have pH of 7.

$KOH\rightarrow K^++OH^-$

As 1 mole of KOH gives 1 mole of $OH^-$

0.01 moles of KOH gives = 0.01 moles of $OH^-$

$pOH=-\log [OH^-]$

$pOH=-\log (0.01)$

$pOH=2$

Also  $pH+pOH=14$

$pH=14-2=12$

Thus pH is 12 and pOH is 2.

Learn more about pH and pOH

https://brainly.com/question/12423271

https://brainly.com/question/13029373

Answer 2

Therefore pH=10 and pOH=4.

Explanation:

Potassium hydroxide is highly soluble ionic compound.

[OH⁻]= 0.01 M

pOH=-log[OH⁻]= -log [0.01]=-(-2)=4

Again pOH+pH=14

        ⇒  4+pH=14

         ⇒  pH=14-4

         ⇒   pH=10

Therefore pH=10 and pOH=4