if the concentration of given solution of kOH is 0.01M.calculate the pOH and pH of the solution
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Answered by
5
Answer:
pH or pOH is the measure of acidity or alkalinity of a solution. Acids have pH ranging from 1 to 6.9 and bases have pH ranging from 7.1 to 14.Neutral substances have pH of 7 KOH→K++OH− As 1 mole of KOH gives 1mole of OH− 0.01 moles of KOH gives =0.01 moles of OH− pOH=−log[OH−] pOH=−log(0.01) pOH=2 Also pH+pOH=14 pH=14−2=12 Thus pH is 12 and pOH is 2.
Explanation:
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Answered by
3
Answer:
pOH = 2
pH = 12
Explanation:
[OH-] = 0.01 M
pOH = - log 0.01
= 2
pH = 14- 2 = 12
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