Question

If the coordinates of one end of a diameter of a circle are (2. 3) and the coordinates of its centre are
(-2.5), then the coordinates of the other end of the diameter are
1) (-6, 7)
2) (6.-7)
3)(6,7)
4)(-6.-7)​

Answer 1

Let the coordinates are = x1,y1

So,,,,

x1+x2/2 = x

x1+2 = -2×2

x1 = -4-2

x1 = -6

Same,,,y1+y2/2 = y

y1+3 = 5×2

y1 = 10-3

y1 = 7

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