Question

please solve this sum.
​

Answer 1

Answer:

We know,

${ \sec( \alpha ) }^{2} - 1 = { \tan( \alpha ) }^{2}$

${ \csc( \alpha ) }^{2} - 1 = { \cot( \alpha ) }^{2}$

➡️ then,

$({ \sec( \alpha ) }^{2} - 1)( { \csc( \alpha ) }^{2} - 1)$

=

${ \tan( \alpha ) }^{2} \times { \cot( \alpha ) }^{2}$

= 1 [Ans]

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