If the cost of banana is increased by 1 per dozen one can get 2 dozens less for rupees 840.Find the original cost of one dozen banana
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let original cost of banana per dozen be x and no. of dozen of banana getting from original price be y.
According to Question
840/x = y (1)
840/x+1 = y-2 (2)
putting value of y from equ. (1) to (2)
840/x+1 = (840 /x) -2
840/x+1 = 840 -2x / x
840x = 840x+840-2x²-2x
2x² +2x -840 = 0
2x² +42x - 40x -840 = 0
2x(x+21) -42(x+20) = 0
(2x-42) (x+20) = 0
x = 21,-20
So,original cost of one dozen banana = x = 20,
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