If the cost of planting the grass in a circular park at the rate of ₹5per m sq is ₹27720.A path of uniform width runs around the park. The cost of gravelling the path at the rate of ₹3.5 per msq is ₹10780.find the cost of fencing the path on both sides at the rate of ₹2.1 per m sq
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area of circular park
= 27720/5 = 5544 m^2
πr^2 = 5544 => r^2 = 5544 ×7/ 22
r^2 = 1764 => r = 42m
area of the path = 10780/3.5
= 3080 m^2
area of the circular park including path
= 5544 + 3080 = 8624m^2
πR^2 = 8624 => R^2 = 8624×7/ 22
R^2 = 2744m^2 => R = 52.38m
length of path to be fenced on both sides
= 2πr + 2πR = 2π(r + R)
= 2×22/7 *( 42 + 52.38)
= 593 m (approx)
cost of fencing 1m = ₹2.1
cost of fencing the both sides of the path= 2.1 × 593 = ₹1245 ( approx.)
Answer: ₹1245
= 27720/5 = 5544 m^2
πr^2 = 5544 => r^2 = 5544 ×7/ 22
r^2 = 1764 => r = 42m
area of the path = 10780/3.5
= 3080 m^2
area of the circular park including path
= 5544 + 3080 = 8624m^2
πR^2 = 8624 => R^2 = 8624×7/ 22
R^2 = 2744m^2 => R = 52.38m
length of path to be fenced on both sides
= 2πr + 2πR = 2π(r + R)
= 2×22/7 *( 42 + 52.38)
= 593 m (approx)
cost of fencing 1m = ₹2.1
cost of fencing the both sides of the path= 2.1 × 593 = ₹1245 ( approx.)
Answer: ₹1245
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