Question

if the cost of (x+1)cameras is rs (xcube +3xsquare +5x+3),then the cost of 1 cameta is

Answer 1

Answer:

$x^2 + 2x +3$

Step-by-step explanation:

Cost of  x+1 camera = $x^{3} +3x^{2} +5x+3$,

No. of cameras = (x+1)

Then, applying simple , unitary method,

we get,

$x^{3} +3x^{2} +5x+3$/(x+1)

which is equal to

$x^2 + 2x +3$