Question

if the Cp value is 20 and mass of oxygen is 64 what is Cv?​

Answer 1

Answer:

3.38 Joule/mol*Kelvin

Explanation:

The mass of oxygen is 64 gm. 1 mole oxygen($O_2$) = 32 gm

Therefore 64 gm oxygen = 2 mole oxygen = n

$C_p-C_v = nR$

$C_p - nR = C_v\\C_p = 20 J/mol*K\\R = 8.31 J/mol*K\\\therefore C_v = C_p - nR = 20-2*8.31 = 3.38 J/mol*K$

Answer 2

As per data given in the question,

We have, given Cp value of oxygen = 20

Mass of oxygen = 64

We have to find the Cv value of oxygen,

As we know that,

Cv value is nothing but the percentage ratio of standard deviation to the mean value.

We also know that,

$C_{p}-C_{v}=n R$

So, from the above given data,

Calculating the Cv value of oxygen,

We will get,

$\begin{array}{l}C_{p}-C_{v}=n R \\C_{p}-n R=C_{v} \\C_{p}=20 \mathrm{~J} / \mathrm{mol} * K \\R=8.31 \mathrm{~J} / \mathrm{mol} * K \\\therefore C_{v}=C_{p}-n R=20-2 * 8.31=3.38 \mathrm{~J} / \mathrm{mol} * K\end{array}$

Hence, Cv value of given element will be 3.38/ mol * K