Question

if the cross section of a canal is trapezium with parallel sides 8em and 16cm and the<br />uween the parallel sides is 10cm. The water flows through this canal at a speed<br />5 km/hour. How much water will flow through it in one hour​

Answer 1

Area of the trepziam =2(8+16)*10     ,2*24*10=480      ,480*5=2400

Answer 2

Given:

Length of parallel sides of trapezium :

= 8 cm and 16 cm

Perpendicular distance between the parallel sides i.e. height :

= 10 cm

Speed of water flow :

= 5 km per hour

To Find :

Amount of water that will flow through it in 1 hour = ?

Solution :

∴The formula for the area of trapezium is :

$A= 2 \times (sum of parallel sides ) \times perpendicular distance between parallel sides$

So using above formula the area of given trapezium will be :

$A= 2\times (8+16)\times 10 cm^{2} \\A=2\times 24 \times 10 cm^{2} \\A= 480 cm^{2}$

Now the water flow at a rate of :

= 5 km per hour

= 500000 cm per hour

∴Volume of water flowing the canal having cross section of trapezium shape :

$= 480 cm^{2} \ times 500000 cm$

$= 240000000 cm^{3}$

∴We know that $1000cm^{3} = 1 l$

So,$24000000cm^{3} =240000 l$

So 240000 liter of water will flow through the canal in 1 hour .