Question

If the cube roots of unity are 1, ω, ω² then the roots of the equation (x –1)³ + 8 = 0, are(a) –1, –1 + 2ω, – 1 – 2ω²(b) –1, – 1, – 1(c) – 1, 1 – 2ω, 1 – 2ω²(d) – 1, 1 + 2ω, 1 + 2ω²

Answer 1

Answer:

Answer => (C)20&30

Step-by-step explanation:

Ok so Her it is,

Let the ratios be 2x and 3x respectively,

so,

\frac{2x+5}{3x+5} = \frac{5}{7}

3x+5

2x+5

=

7

5

so,

7(2x+5) = 5(3x+5)

14x + 35 = 15x + 25

14x - 15x = 25 - 35

-x = -10

x = 10

then thde numbers are 20 & 30 respectively..