Question

if the current flowing in a conductor increases by 10 % by what percent wil the power icrease

Answer 1

the answer is 5 %........

Answer 2

Answer:

The percentage increase in the power of conductor is equal to 21%.

Explanation:

Consider, the initial current flowing in a conductor $=I$

After the 10% increase in the current through conductor,

Then current becomes:  $I'=I+I(\frac{10}{100} )$

⇒    $I'=I+I(0.1)$

⇒    $I'=1.1I$

Now, when current was $I$ then power will be $P$:

Initial Power, $P=I^{2}R$      where R is the resistance in conductor.

Final power, $P'=I'^{2}R$

⇒   $P'=(1.1I)^{2}R$

⇒    $P'=1.21I^{2}R$

Percentage increase in the power   $=\frac{P'-P}{P}*100$  

                                                          $=(\frac{1.21P-P}{P})*100$

                                                          $=0.21*100$

                                                          $=21$%

Therefore, the rise in the power consumption of conductor is equal to 21%.