Question

if the current I through a resistor is increased by 100 percentage then find the increase in power dissipated

Answer 1

Increased Power= New power- Old power (2I)squareR -I square R =4IsquareR-IsquareR. =3squareR. Percentage increased = new power/old power×100=3 / 1×100%=300%........

Answer 2

Answer= 300 %

Here current flowing through the resistor is I then

P1 = I^2R

If the current flowing through the resistor is increased by 100%

Then current =

=I + (100% × I)

=I + (I x 100/100)

= 2I

Now power is

P2 = (2I)^2R

= 4I2R

Change in percentage of power is

=(P2 - P1) /( P1) x 100%

= (4I2R - I2R)/(I2R) x 100%

= 300%