if the cylinder took 3 complete revolutions on the ground, find the area of the ground. whose radius is 14 and height is 14
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Answered by
1
Answer:
I have mentioned the answer in the pic..
hope it helps..
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Answered by
1
Answer:
3696
Step-by-step explanation:
area of ground=no.of revolution*surface area of cylinder
area=3*(2*pi*r*h)
area=3*(2*(22/7)*14*14)
=3969
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