If the density of a certain gas at 30.c and 768 torr is 1.35kg/m3 its density at STPwould be
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Answered by
173
We can use the formula PV = nRT.
Let us assume that V = 1 liter.
PV = nRT
n = PV/RT = (768/760 atm) x (1 L) / [(0.0821 Latm/mole K) x (303K)] = 0.0406 moles of gas
= 1 L x (1 m³ / 1000 L) x (1.35 kg / 1 m³ ) x (1000 g / 1 kg) = 1.35 g
Thus, MW of gas = 1.35 g / 0.0406 moles = 33.3 g/mole.
At STP, n = PV / RT = (1.0 atm) x (1 L) / [(0.0821 Latm/moleK) x (273K)] = 0.0446 moles
= 0.0446 moles x (33.3 g / mole) x (1 kg / 1000 g) = 0.00149 kg
= 0.00149 kg / 1 L x (1000 L / 1 m³) = 1.49 kg / m³
Let us assume that V = 1 liter.
PV = nRT
n = PV/RT = (768/760 atm) x (1 L) / [(0.0821 Latm/mole K) x (303K)] = 0.0406 moles of gas
= 1 L x (1 m³ / 1000 L) x (1.35 kg / 1 m³ ) x (1000 g / 1 kg) = 1.35 g
Thus, MW of gas = 1.35 g / 0.0406 moles = 33.3 g/mole.
At STP, n = PV / RT = (1.0 atm) x (1 L) / [(0.0821 Latm/moleK) x (273K)] = 0.0446 moles
= 0.0446 moles x (33.3 g / mole) x (1 kg / 1000 g) = 0.00149 kg
= 0.00149 kg / 1 L x (1000 L / 1 m³) = 1.49 kg / m³
Answered by
38
Answer:
Explanation:
p1v1/t1= p2v2/t2...then we know that v1 =m/d1,v2=m/d2....... P1=768/760by ......760torr =1atm. P2 =at stp 1 atm. T1=303 ,T2=at stp 273 then this information put in formula so.....p1m/d1 T2=p2m/d2 T2. Then... Find answer 1.48 kg/m3......i hope u clear
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