Question

If the density of an object is 900 kg/m3 and the volume is 3 m^3 what is the mass?

Please show the full work done.

Answer 1

Answer:

Let the volume of the cube be V and the fraction of cube outside water be f.

Thus, volume of ice inside water = volume of water displaced =(1−f)V

Under equilibrium,

Weight of ice = Weight of water displaced

⟹Vρ

ice

g=(1−f)Vρ

water

g

⟹(1−f)=

10

9

⟹f=

10

1

Thus, the percentage of volume outside water =10%

Answer 2

d = 900 kg/m³

v = 3m³

$density = \frac{mass}{volume}$

$mass = density \times volume$

$mass = 900 \times 3 \\ mass = 2700 \: kg$