if the density of water is 1 g cm cube then the volume occupied by one molecule of water is approximately
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1 molecule of water=1/NA or 1/6.022x10^23moles
and,
1/NAx molecular mass of water= 1/6.022x10^23x18=18/6.022x10^23
=3x10^-23(approximately)
now volume=3x10^-23/1= 3x10^-23
and,
1/NAx molecular mass of water= 1/6.022x10^23x18=18/6.022x10^23
=3x10^-23(approximately)
now volume=3x10^-23/1= 3x10^-23
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