Question

Without actually calculating the cubes, find the values of 55 3 - 25 3 - 30 3

Answer 1

go through the solution step by step

Answer 2

Answer:

we know that,

X+y+z=0,

x^3+y^3+z^3=3xyz

according to the question,

let X=55, Y=-25 and Z=-30

X+y+z=55+(-25)+(-30)

=55-25-30

=55-55

=0

so, X+y+z=0

therefore, x^3+y^3+z^3=3xyz

=55^3+(25)^3+(-30)^3

=3×55×-25×-30

=165×750

Ans =123750