if the diagnol of a square is 8cm. find
length
perimeter
area
Answers
To Find:-
- Area and Perimeter
Given:-
Diagonal:- 8cm
Solution:-
We know
In a square all angles are equal,and each are of 90°
therefore
Consider ∆ABC
where a=90°
We know
In a right triangle,The Longest side(side opposite to 90°) known As Hypotenuse can be find out through Pythagoras Theorem that is
Hypotenuse² = s²+s²)
Where s & s are the remaining two sides of a triangle
Here
BC= Hypotenuse
AB & AC = remaining sides
Therefore
BC²=AB²+AC²
Since it's a square,then AB=AC,
that is
8²=s²+s²=2s²
2s²=64
s²=64÷2=32
s=√32
s=4√2
Therefore the length of one side= 4√2cm
- Now to Find Perimeter
we know
Perimeter of a square= 4s
where s=semi perimeter
that is
4×4√2
16√2
Therefore the perimeter is 16√2cm
- Now To Find Area
We know
Area of a square= s²
substituting the value
that is
Area= (4√2)²
Area=16×2=32cm²
Therefore the Area is 32cm²
Hope it helps
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