Question

If the diagnols of rhombus are 6cm and 8cm , it's area will be

Answer 1

Answer:

The Diagonals of rhombus is 6,8cm

The area of triangle is given as

2

1

×6×8

3×8=24cm

2

The diagonals right bisect each other

So the sides of Right Triangle formed by diagonals and sides are 3,4

So by pythagoras theorem

Side

2

=3

2

+4

2

side

2

=16+9

side

2

=25

side=

25

Side=5

Answer 2

Answer- The above question is from the chapter 'Area and Perimeter'.

Concept used: Let d₁ be first the diagonal of rhombus and d₂ be second diagonal.

Area of Rhombus = $\frac{d_{1} \times d_{2}}{2}$

Given question: If the diagonals of rhombus are 6 cm and 8 cm , its area will be _____ .

Solution: For a rhombus, d₁ = 6 cm

d₂ = 8 cm

Area of Rhombus = $\frac{d_{1} \times d_{2}}{2}$

Area of Rhombus = $\frac{6 \times 8}{2}$

Area of Rhombus = $\frac{48}{2}$

Area of Rhombus = 24 cm²

∴ If the diagonals of rhombus are 6 cm and 8 cm , its area will be 24 cm².