If the diagonal of a parallelogram are equal then show that is a rectangle
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Answer:
□ ABCD is a parallelogram
consider Δ ACD and Δ ABD
AC = BD .... (given)
AB = DC .... (opposite sides of parallelogram)
AD = AD .... (common side)
∴Δ ACD ≅Δ ABD (SSS test of congruence)
∠ BAD = ∠ CDA .... (cpct)
∠BAD+∠CDA=180 ∘ [Adjacent angles of parallelogram are supplementary]
so ∠ BAD and ∠ CDA are right angles as they are congruent and supplementary.
Therefor, □ ABCD is a rectangle since a
parallelogram with one right interior angle is a rectangle.
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Answer:
By Making It's all angles same.
Explanation:
Yes if four of the diagonals are same then mark their all the angles so that their sum is = 360 . Then it will become a rectangle.
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