if the diagonal of a parallelogram are equall then show that it is a rectangle
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pahiroy1221:
very nice
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prove properly.....imagine .....let us take a paralleogram as ABCD..in that DA andCB are diagnols in which they intersects at O....in triange ABO and triangle COD angle COD is equal to angle AOB....angleOCD is equal to angle ABC because they are alternate angle..side CD is equal to side AB .....therefore by ASA postulate triangle COD is congruent to triangle AOB....by axiom 1 triangle AOD is congruent to triangle BOC...AO=OC and BO=OD since diognals
since diognal are equal and opposite sides are equa...there fore it is rectangle
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if the diagonals of a parallelogram are equal then the figure is a rectangle.
proof: the two diagonals of parallelogram forms a rectangle
these two triangles are congruent by sss congruency property.
==>by ASP the corresponding angles become 90 degrees
HENCE the parallelogram forms a rectangle
proof: the two diagonals of parallelogram forms a rectangle
these two triangles are congruent by sss congruency property.
==>by ASP the corresponding angles become 90 degrees
HENCE the parallelogram forms a rectangle
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