Question

if the diagonal of a square is 6/2 then the perimeter of square is ​

Answer 1

Answer:

Diagonal of the square =

6

√

2

cm

Let the side of the square be a.

By Pythagoras theorem,

(

6

√

2

)

2

)

=

a

2

+

a

2

=

2

a

2

⇒

a

= 6 cm

Perimeter of the square = 4a = 24 cm

Perimeter of the square = Perimeter of triangle

Semi perimeter of the triangle =

24

2

= 12 cm

Answer 2

Answer:

4√ 4.5 or √72

Step-by-step explanation:

Using pythogorean therum, we know that A^2 + B^2 = C^2

Then let the side be s

S^2+S^2=36/4

S^2+S^2=9

2*S^2=9

S^2=4.5

S= √ 4.5

perimeter= 4*S

=4*√4.5

=4√ 4.5 or √72