if the diagonal of llgm are equal,t hen it's a rectangle
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[Please mark as Brainliest answer.]
In parallelogram ABCD,
Consider triangles ADC and ADB
AC = BD [Given]
AB = DC [sides of a parallelogram]
AD = AD [Common ]
∴ ΔABD ≅ ΔDCA [By SSS]
∠BAD = ∠CDA [C.P.C.T]
∠BAD + ∠CDA = 180° [Adjacent ∠’s of a || gm .]
So,
∠BAD = ∠CDA = 90
#Please Mark as Brainliest answer#
[Please mark as Brainliest answer.]
In parallelogram ABCD,
Consider triangles ADC and ADB
AC = BD [Given]
AB = DC [sides of a parallelogram]
AD = AD [Common ]
∴ ΔABD ≅ ΔDCA [By SSS]
∠BAD = ∠CDA [C.P.C.T]
∠BAD + ∠CDA = 180° [Adjacent ∠’s of a || gm .]
So,
∠BAD = ∠CDA = 90
#Please Mark as Brainliest answer#
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