Question

If the diagonal of parallelogram are equal,then show that it is a rectangle.
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

$\huge\mathtt\red{Answer}$

Let as draw ABCD is a parallelogram in which AC & DB are two equal diagonals.

In △ABC & △DCB

AC = DB (Given)

BC = BC (Common)

AB = DC (opposite side of 11gm)

△ABC ≅ △DCB ( By SSS rule)

∠ABC = ∠ DCB [ C. P. C. T]

∠ABC + ∠DCB = 180° = [ CO. Interior]

∠ABC + ∠ABC = 180°

2∠ABC = 180 °

$∠ABC = <strong> \: \cancel \frac{180}{2}$

∠ABC = 90°

∠ABC = 90° = ∠DCB = 90°

∠ABC = ∠ DCB

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎‎‎ ‎‎ ‎★ Hence proved ★