if the diagonal of parallelogram bisect each other then the quadrilateral is a parallelogarm
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Given: A quadrilateral ABCD whose diagonals AC and BD bisect each other at point O. i.e., OA = OC and OB = OD
To prove: ABCD is a parallelogram i.e., AB ║ DC and AD ║ BC.
Proof: In ∆AOB and ∆COD
OA = OC [Given]
OB = OD [Given}
∠AOB = ∠COD [Vertically opposite angles]
⇒ ∆AOB ≅ ∆COD [By SAS] ⇒ ∠1 = ∠2 [By cpctc]
But these are alternate angles and whenever alternate angles are equal, the lines are parallel.
∴ AB is parallel to DC i.e., AB ║ DC Similarly, ∆AOD ≅ ∆COB [By SAS]
⇒ ∠3 = ∠4 But these are also alternate angles ⇒ AD ║ BC AB ║ DC and AD ║ BC
⇒ ABCD is a parallelogram.
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