Question

If the diagonala of a rhombus are 6m and 8m, then its side is

Answer 1

${\huge {\mathfrak {Answer :-}}}$

The side will be

= [ (6/2)^2 + (8/2)^2 ]^1/2

= [ 3^2 + 4^2 ]^1/2

= [ 9 + 16 ]^1/2

= 25^1/2

= 5.

➡️ Side of the rhombus is 5 m.

$<i>$ That's it..

Answer 2

Step-by-step explanation:

The side will be

= [ (6/2)^2 + (8/2)^2 ]^1/2

= [ 3^2 + 4^2 ]^1/2

= [ 9 + 16 ]^1/2

= 25^1/2

= 5.

.