x2+3x-(m+2)(m+5) =0 find the roots plss fast
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x^2 +3x - (m+2)(m+5) = 0
=> x^2 + (m+5)x - (m+2)x - (m+2)(m+5) = 0
=> x (x + m+5) - (m+2)(x+m+5) = 0
=> (x+m+5)(x-m-2) = 0
=> x = - m-5. and m+2
Roots are (-m-5) and (m+2)
=> x^2 + (m+5)x - (m+2)x - (m+2)(m+5) = 0
=> x (x + m+5) - (m+2)(x+m+5) = 0
=> (x+m+5)(x-m-2) = 0
=> x = - m-5. and m+2
Roots are (-m-5) and (m+2)
achuaiswarya112:
It should be done using b2-4ac formula shouldnt it ???
it can be done by any of two method, splitting of middle term or quadratic formula
Hmm k thanks
Answered by
6
x^2 +3x - (m+2)(m+5) = 0
=> x^2 + (m+5)x - (m+2)x - (m+2)(m+5) = 0
=> x (x + m+5) - (m+2)(x+m+5) = 0
=> (x+m+5)(x-m-2) = 0
=> x = - m-5. and m+2
Roots are (-m-5) and (m+2)
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