If the diagonals AC and BD of a quadrilateral ABCD are perpendicular to one
another, prove that area of the quadrilateral = 1/2 AC* BD.
Answers
Answered by
1
Answer:
A quadrilateral ABCD in which the diagonals AC and BD intersect at O assume that AO = OC , BO = OD . AC perpendicular BD. To prove : ABCD is a rhombus. Proof : Since the diagonals AC and BD of quadrilateral ABCD bisect each other at right angles.
Answered by
0
Answer:
If the diagonals AC and BD of a quadrilateral ABCD are perpendicular to one
Similar questions