Question

If the diagonals of a parallelogram bisect each other at 90 degree , then show that it is a rhombus

Answer 1

Answer:

Let ABCD be a quadrilateral whose diagonals bisect each other at right angles. Therefore, ΔAOB ≅ ΔCOB by SAS congruence condition. ... Thus, ABCD is rhombus as it is a parallelogram whose diagonals intersect at right angle.

Step-by-step explanation:

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