if the diagonals of a parallelogram intersect at right angle. prove that it is a rhombus.. plzz solve it fast today evng is my tution.
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GIVEN:a parallelogram ABCD in which daigonals AC and BD intersect at right angle at O
TO PROVE: ABCD is a rhombus
PROOF: IN TRIANGLE AOD and AOB
OA=OA (COMMON)
<AOD= <AOB =90
TRIANGLE AOD IS CONGRUENT TO TRIANGLE AOB BY (RHS CONGRUENCY)
AD=AB (CPCT)
SIMILARLY AB=BC=CD=DA
TO PROVE: ABCD is a rhombus
PROOF: IN TRIANGLE AOD and AOB
OA=OA (COMMON)
<AOD= <AOB =90
TRIANGLE AOD IS CONGRUENT TO TRIANGLE AOB BY (RHS CONGRUENCY)
AD=AB (CPCT)
SIMILARLY AB=BC=CD=DA
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hrik2:
i thnk its nt correct
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