if the diagonals of a rhombus are 10cm and 8cm then find its area
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Given that ;
The diagonals of a rhombus are 10 cm and 8 cm.
d₁ = 10 cm
d₂ = 8 cm
We know that,
The area of rhombus is given by dividing the product of diagonals by 2.
We have -
Area of rhombus = \sf \dfrac{1}{2} * d_1 * d_2
2
1
∗d
1
∗d
2
⇒ Area of rhombus = \sf \dfrac{1}{2}*10*8
2
1
∗10∗8
⇒ Area of rhombus = \sf \dfrac{1}{2}*80
2
1
∗80
⇒ Area of rhombus = 40 cm²
Hence, the area of rhombus is 40 cm².
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