Question

If the diagonals of a rhombus are 7cm and 12cm, then find the area of rhombus​

Answer 1

$\sf\Large{\underline{\underline{Question}}}:-$

If the diagonals of a rhombus are 7cm and 12cm, then find the area of the rhombus.

$\sf\Large{\underline{\underline{Solution}}}:-$

Given :-

Here ,

$\ d_{1} = 7cm \\ \\ \ d_{2} = 12cm$

where $\ d_{1} \: and \ d_{2} \: are \: the \: length \: of \: the \: diagonals$

To find :-

Area of the rhombus

Solution:-

We know that,

Area of a rhombus = $\sf\frac{1}{2} × \ d_{1} × \ d_{2}$

= $\sf\frac{1}{2} × 7 × 12$

= $\sf\frac{1}{\cancel{2}} × 7 × \cancel{12}$

= $\sf\: 42cm{}^{2}$

$\sf{\red{\therefore{\boxed{Area \: of \: the \: rhombus = 42cm{}^{2}}}}}$

$\pink{Hope \: it \: helps}$

Answer 2

Answer:

Hence, value of area of Rhombus will be 42 Sq. cm

Step-by-step explanation:

In context to question asked,

We have to determine the area of rhombus.

As per data given in the question,

We have,

Diagonals of rhombus are 12 cm and 7 cm

As we know that,

Rhombus is a quadrilateral whose all sides are equal.

The sum of all the angles of the rhombus is 360 degree.

As we have,

Formula for finding the area of rhombus is $A = \frac{pq}{2}\\Where\:p\:and\:q \:are\:diagonals\:of\:Rhombus$

So, for determining the value of area of rhombus we will put the value of diagonals given in the question in above formula,

Thus we will get,

$A = \frac{pq}{2}\\=>A = \frac{12\times 7}{2} = \frac{84}{2} = 42\:cm^2$