Math, asked by KsSingh0, 5 months ago

If the diagonals of a rhombus are of length 24 cm in 18 cm. find the length of the side of the rhombus and hence find its perimeter.

Give me Explanation.

Answers

Answered by shreyadhallu35
2

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Answered by Auяoяà
13

✯SOLUTION :

We know that in a rhombus the diagonals bisect each other at right angle (90°).

Thus,in the figure attached there is triangle AOB that is a right angled triangle and contains AO = 12cm ,OB = 9cm abd AB is hypotenuse here.

Thus,By using Pythagorean theorem ,we get :

↬AB² = AO² + OB²

↬AB² = (12)² + (9)²

↬AB² = 144 + 81

↬AB² = 225

↬AB = √225

↬AB = √15×15

↬AB = 15 cm

∴ the side of the rhombus is 15 cm respectively.

✯Now,we have to find the Perimeter.

We know that,

•Perimeter of rhombus = 4 × side

•Perimeter of rhombus = 4 × 15 = 60 cm

You must know :

→The all sides of a given rhombus are equal.

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