If the diagonals of a rhombus are of length 24 cm in 18 cm. find the length of the side of the rhombus and hence find its perimeter.
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✯SOLUTION :
We know that in a rhombus the diagonals bisect each other at right angle (90°).
Thus,in the figure attached there is triangle AOB that is a right angled triangle and contains AO = 12cm ,OB = 9cm abd AB is hypotenuse here.
Thus,By using Pythagorean theorem ,we get :
↬AB² = AO² + OB²
↬AB² = (12)² + (9)²
↬AB² = 144 + 81
↬AB² = 225
↬AB = √225
↬AB = √15×15
↬AB = 15 cm
∴ the side of the rhombus is 15 cm respectively.
✯Now,we have to find the Perimeter.
We know that,
•Perimeter of rhombus = 4 × side
•Perimeter of rhombus = 4 × 15 = 60 cm
You must know :
→The all sides of a given rhombus are equal.
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