If the diagonals of a rhombus r of length 20 cm and 14 cm. find the length of the side of the Rhombus and hence find its perimeter?
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The diagonals intersect at right angle:
a² + b² = c²
c² = (20 ÷ 2 )² + (14 ÷ 2)²
c² = 149
c = √149
c = 12.2 cm
FInd the perimeter :
The length of the 4 sides of a rhombus are equal
Perimeter = 4 x length
Perimeter = 4 x 12.2 = 48.8 cm
Answer: The length is 12.2 cm and the perimeter is 48.8cm
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