If the diagonals of parallelogram are equal in length,show that the parallelogram is a recyangle
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lets say, ABCD is a parallelogram
Given that the diagonals AC and BD of parallelogram ABCD are equal in length .
Consider triangles ABD and ACD.
AC = BD [Given]
AB = DC [opposite sides of a parallelogram]
AD = AD [Common side]
∴ ΔABD ≅ ΔDCA [SSS congruence criterion]
∠BAD = ∠CDA [CPCT]
∠BAD + ∠CDA = 180° [Adjacent angles of a parallelogram are supplementary.]
So, ∠BAD and ∠CDA are right angles as they are congruent and supplementary.
Therefore, parallelogram ABCD is a rectangle since a parallelogram with one right interior angle is a rectangle.
Given that the diagonals AC and BD of parallelogram ABCD are equal in length .
Consider triangles ABD and ACD.
AC = BD [Given]
AB = DC [opposite sides of a parallelogram]
AD = AD [Common side]
∴ ΔABD ≅ ΔDCA [SSS congruence criterion]
∠BAD = ∠CDA [CPCT]
∠BAD + ∠CDA = 180° [Adjacent angles of a parallelogram are supplementary.]
So, ∠BAD and ∠CDA are right angles as they are congruent and supplementary.
Therefore, parallelogram ABCD is a rectangle since a parallelogram with one right interior angle is a rectangle.
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