if the diagonals of rhombus are 16cm and 30cm find its perimeter
Answers
Answered by
6
by Pythagoras theory
square of x =square of base+square of side
square of x=square of 8 +square of 15
square of x=64+225
square of x=289
x=√289
x=17
we got side 17 cm
perimeter=4*side
=4*17
=68cm
square of x =square of base+square of side
square of x=square of 8 +square of 15
square of x=64+225
square of x=289
x=√289
x=17
we got side 17 cm
perimeter=4*side
=4*17
=68cm
Attachments:
Similar questions