If the diameter of a resistance wire is halved then its resistance becomes what?
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Answer:
HEY GUD NOON DUDE.....
Explanation:
RESISTANCE = RESISTIVITY * LENGTH/AREA
RESISTANCE ∝1/RADIUS² DIAMETER = RADIUS *2
RESISTANCE ₁ ∝1(/DIAMETER₁/2) ²..............(1)
RESISTANCE ₂ ∝1/(DIAMETER₂/2)² DIAMETER₂=DIAMETER₁/2
RESISTANCE ₂ ∝1/(DIAMETER₁/4)²............(2)
(1)/(2)
RESISTANCE₁/RESISTANCE₂= 1*(DIAMETER₁/4)²/(DIAMETER₂/2)²
= 4/16
= 1/4
RESISTANCE ₂= 4*RESISTANCE ₁.
HOPE THIS HELPS.
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