If the diameter of a sphere is decreased by 25% then by what percent it's curved area would decrease?
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first account the difference between the original surface area and the increased surface area and then use a formula increase I decrease equals to increase or decrease divided by original value x 100
Silchar diameter is decreased by 25% there for you will write diameter that is d equals to 25% of d minus d
and then you will get the radius that is R1 3 by 4 r
and then take out the surface area of the original and increased
Silchar diameter is decreased by 25% there for you will write diameter that is d equals to 25% of d minus d
and then you will get the radius that is R1 3 by 4 r
and then take out the surface area of the original and increased
adityajarwal2004:
Can I get solution
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d is equals to di - 25% of d which is equals to d - 25 / 100 x d which is equals to 3 by 4 d therefore D1 equals to 3 / 4 d and we know that b is equal to twice of our so we will put our in place of that is 2 r =3/4 r therefore r1 = 3/4 r. Suface area(SA) of original is 4pier sq. and the SA of incresed is 4pie r sq. put the value of r that is 3/4r sq. then the area will be 9pier sq. /4 . the area decresed is equal to SA1 MINUS SA and then the answer will be 7pie r sq./4 .Then put the formula
is it ok
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