Math, asked by mandalsuphal508, 20 days ago

if the difference between the present age of a mother and her daughter is 20 years and the product of their age 44 years find the present age of mother and daughter

Answers

Answered by srinidhivijaychander
0

Answer:

mother=22,son=2

Step-by-step explanation

product=44

therefore , factors of 44 is answer

2and22 are factor of 44

2+20=22

Answered by MysticSohamS
0

Answer:

your answer is as follows

pls mark it as brainliest

Step-by-step explanation:

to \: find :  \\ present \: ages \: of \: mother \: and \: \\ her \:  daughter \\  \\ let \: the \: present \: ages \: of \: mother \:  \\ be \:  x \: years \: and \: that \: of \: her \\ daughter \: be \: y \: years \\  \\ according \: to \: first \: case \\ x - y = 20 \\ x = y + 20 \:  \\  \\ according \: to \: second \: case \\ xy = 44 \\  \\ y(y + 20) - 44 = 0 \\ \\  y {}^{2}  + 20y - 44 = 0 \\  \\ y {}^{2}  + 22y - 2y - 44 = 0 \\  \\ y(y + 22) - 2(y + 22) = 0 \\  \\ (y + 22)(y - 2) = 0 \\  \\ y =  - 22 \:  \: or \:  \: y = 2 \\  \\ since \: age \: is \: never  \: negative \\ y =  - 22 \:  \: is \: absurd

substituting \: value \: of \: y \: in \\ x = y + 20 \\ we \: get \\  \\ x = 22

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